we dissolve 18.9 g of li, o (molar mass = 29.9 g/mol) ini sufficient water to make 650 ml of
solution
question
what is the molarity of the solution?

The solution has a molarity of 0.97 M

Explanation:

Step 1: Given data

Mass of LiO = 18.9 grams

Molar mass of LiO = 29.9 g/mol

Volume = 650 mL = 0.650 L

Step 2: Calculate number of moles

Number of moles of LiO = Mass of LiO / Molar mass of LiO

Moles LiO = 18.9 grams / 29.9 grams/mol

Moles LiO = 0.6321 moles

Step 3: Calculate molarity

Molarity = Number of moles per volume

Molarity = Moles per liter

Molarity LiO = Moles LiO / volume solution

Molarity LiO = 0.6321 mol / 0.65 L

Molarity LiO = 0.97 M

The solution has a molarity of 0.97 M