How many moles of zncl, will be produced from 23.0 g of zn, assuming cucl, is available in excess?

23 g of Zn will produce 0.352 mole of zinc chloride.      

Explanation:

Given data:

mass of Zn = 23 g

Moles of ZnCl = ?

Solution:

Chemical equation:

2Zn + CuCl₂ → 2ZnCl + Cu

Number of moles of Zn:

Number of moles of Zn = mass/ molar mass

Number of moles of Zn = 23 g / 65.38 g/mol

Number of moles of Zn = 0.352 mol

now we will compare the moles of ZnCl with Zn because it is limiting reactant.

                         Zn       :      ZnCl  

                         2         :        2

                         0.352 :        0.352

So 23 g of Zn will produce 0.352 mole of zinc chloride.      

the reaction mixture contains some ammonia, plus a lot of unreacted nitrogen and hydrogen. the mixture is cooled and compressed, causing the ammonia gas to condense into a liquid. the liquefied ammonia is separated and removed. the unreacted nitrogen and hydrogen are then recycled back into the reactor .