How many atoms are in 0.750 moles in zinc?

4.52 × 10^23 atoms

Concept being tested: Moles and Avogadro's number

From the question we are given;

We are required to calculate the number of atoms of Zinc

Therefore;

1 mole of Zinc = 6.022 × 10^23 atoms

To calculate the number of atoms we need to multiply the number of moles with the Avogadro's constant.

 = 0.750 moles × 6.022 × 10^23 atoms

= 4.52 × 10^23 atoms

Therefore; 0.750 moles of Zinc contains 4.52 × 10^23 atoms

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