The value of δ°′δg°′ for the conversion of glucose-6-phosphate to fructose-6-phosphate (f6p) is +1.67 kj/mol+1.67 kj/mol . if the concentration of glucose-6-phosphate at equilibrium is 1.85 mm1.85 mm , what is the concentration of fructose-6-phosphate? assume a temperature of 25.0°c25.0°c .

Answer : The concentration of fructose-6-phosphate is 0.275 mM

Explanation :

First we have to calculate the value of equilibrium constant.

The relation between the equilibrium constant and standard Gibbs free energy is:

where,

= standard Gibbs free energy  = +1.67 kJ/mol = +1670 J/mol

R = gas constant  = 8.314 J/K.mol

T = temperature  =

K = equilibrium constant = ?

Now put all the given values in the above formula, we get:

Now we have to calculate the concentration of fructose-6-phosphate.

The expression of equilibrium constant is:

Therefore, the concentration of fructose-6-phosphate is 0.275 mM

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explanation:

this is because the buildings or plants could catch on fire and the buildings would most likely collapse. lastly ash would fall because all the burning would cause ash to fall from the sky.

hope this .