Determine the electron geometry (eg) and molecular geometry (mg) of the underlined carbon in ch3cn. determine the electron geometry (eg) and molecular geometry (mg) of the underlined carbon in ch3cn. eg = tetrahedral, mg = bent eg = linear, mg = linear eg = bent, mg = tetrahedral eg = linear, mg = bent eg = trigonal planar, mg = tetrahedral

CH3 : Tetrahedral

CN : Linear

Explanation:

The electron geometry of the given carbons in the structure would be same as molecular gemometry as there is no lone pair on carbon.

The methyl carbon is tetrahedral and is sp3 hybridized.

The nitrile carbon is linear as it is sp hybridized (triple bonded).

There is no carbon with trigonal geometry or bent geometry.

explanation:

let the different atoms be x and y. each with four protons and same mass will be represented as follows.

mass number is number of protons + number of neutrons.

            and  

since, it is given that one has a negative charge while the other is neutral. therefore, there will be increase in number of protons and the atom will be represented as follows.

according to periodic table, mass number of beryllium is 9 and it has atomic number 4 so, the atoms will be and .  

the protons and neutrons will be located inside the nucleus whereas the electrons will be revolving around the nucleus.