A0.773 mol sample of xe(g) initially at 298 k and 1.00 atm is held at constant volume while enough heat is applied to raise the temperature of the gas by 20.1 k. assuming ideal gas behavior, calculate the amount of heat in joules (q) required to affect this temperature change and the total change in internal energy, ? u. note that some books use ? e as the symbol for internal energy instead of ? u.

q= ? u=

Answer : The value of is 193.8 J and 193.8 J respectively.

Explanation : Given,

Moles of sample = 0.773 mol

Change in temperature = 20.1 K

First we have to calculate the heat absorbed by the system.

Formula used :

where,

q = heat absorbed by the system = ?

n = moles of sample = 0.773 mol

= Change in temperature = 20.1 K

= heat capacity at constant volume of Xe (mono-atomic molecule) =

R = gas constant = 8.314 J/mol.K

Now put all the given value in the above formula, we get:

Now we have to calculate the change in internal energy of the system.

As we know that, work done is zero at constant volume. So,

Therefore, the value of is 193.8 J and 193.8 J respectively.

the molecules move in straight line until they collide with each other or with the walls of the container. collisions are perfectly elastic; when two molecules collide, they change their directions and kinetic energies, but the total kinetic energy is conserved.

explanation: