Consider the reaction c12h22o11(s)+12o2(g)→12co2(g)+11h2o (l) in which 10.0 g of sucrose, c12h22o11, was burned in a bomb calorimeter with a heat capacity of 7.50 kj/∘c. the temperature increase inside the calorimeter was found to be 22.0 ∘c. calculate the change in internal energy, δe, for this reaction per mole of sucrose.

the change in internal energy per mole of sucrose is 5989 KJ/mol

Explanation:

Since the calorimeter is a bomb calorimeter , where the volume remains constant

ΔE= Qrx

And assuming no heat losses to the surroundings

Qv + Qrx = 0

Cc*ΔT - Qrx = 0 ,

Qrx = Cc * ΔT = 7.50 KJ/°C * 22 °C = 165 KJ

the change in internal energy is calculated dividing by the number of sucrose moles involved n. the molecular weight of sucrose is

Mw= 12* 12g/mol + 22* 1g/mol + 11* 16 g/mol = 342 g/mol

n = m / Mw = 10 g / 342 g/mol = 0.029 mol

the change in internal energy per mole of sucrose is

Δe= ΔE/n = 165 KJ/0.029 mol = 5989 KJ/mol

let that person have a turn to speak : )

the answer is 1260

you spend 7 hours in school for 1 school day with 5 school days in 1 school week with 36 school weeks in a school year.

7*5*36= 1260 it's all about multiplying