Achemistry student found the density of freon-11 (cfcl3) to be 5.58 g/l under her experimental conditions. her measurements showed that the density of an unknown gas was 4.38 g/l under the same conditions. what is the molar mass of the unknown?

52.56 g/mol

Explanation:

Given:

density of CFCL3=5.58 g/mol

density of unknown gas=4.38 g/mol

From ideal gas law PV=nRT

N=number of moles=mass/molar mass

P=pressure

R=gas constant

T=Temperature

Therefore PV= (mass/molar mass)RT……1

Making molar mass the subject of the equation

Molar mass=(mass/V)RT/P……….2

Since density ƥ=mass/volume. Substitute in equation 2 above

Molar mass= ƥ × RT/P……..3

Since the conditions applied does not change as stated in the question. let k=RT/P

Substituting in equation 3, molar mass= ƥ × k……..4

For FREON-11(CFCL3)

Atomic weights are

C=12

F=19

CL3=3*12=36

Molar mass of CFCL3=12+19+36=67

Substitute in equation 4

67=5.58 × k

K=12 L/mol

Applying equation 4 for the unknown gas with 4.38g/mol density

Molar mass=4.38 × 12=52.56 g/mol

in scientific notation, the value of the  speed of light in a vacuum

  will be written as 2.995 * 10^8. when this value is represented in the form of

  a * 10^b, then, a = 2.995 and b = 8.

the value of the speed of light in a vacuum given above can also be rounded up to approximately 300000000. in this case, the scientific notation will be written as 3 *10^8.

58750.08068 is the answer i think