Consider two different containers, each filled with of . one of the containers is rigid and has constant volume. the other container is flexible (like a balloon) and is capable of changing its volume to keep the external pressure and internal pressure equal to each other. if you raise the temperature in both containers, what happens to the pressure and density of the gas inside each container? assume a constant external pressure.

In the rigid container : pressure increases when temperature increases and density remains constant

In the flexible container: pressure remains constant and density decreases when temperature increases

Explanation:

Using the Ideal gas law

P= absolute pressure, V=volume , n= number of moles (mass) , R=constant , T= absolute temperature

And

D= Density , m = mass , V= volume

In both containers, since they are sealed, the mass is kept inside and remains constant --> n= constant and m= constant

- In the rigid container , V = constant , therefore

And thus absolute pressure increases with absolute temperature

Regarding density

Thus density remains constant

- In the flexible container , P = constant , therefore

but also

And thus density decreases with temperature

answer: the rate of diffusion increases with increase in temperature.

increase in temperature, increases the molecular/particles speed (kinetic energy. diffusion means movement of particles through the material.

generally, the heavier the particle the more it interacts with the environment and more the temperature matters. so higher temperature results in higher diffusion.

idk what the question is about