Compound o (c6h8) reacts with two molar equivalents of hydrogen in the presence of a catalyst to produce p (c6h12). the proton-decoupled 13c spectrum of o consists of two singlets, one at δ 26.0 and one at δ 124.5. in the dept 13c spectrum of o the signal at δ 26.0 appears as a ch2 group and the one at δ 124.5 appears as a ch group. note: all structures should be drawn with no bonds between carbon and hydrogen. draw the correct structure for o and p

Cyclohexadiene is converted to cyclohexane

Explanation:

Let's go in order of statements mentioned in question.

As we see from the formula it is a hydrocarbon. If it reacts with two equivalents of hydrogen, then it is either an alkyne or diene. Due to number of protons and only two signals in C13 NMR it must be a cyclic diene with only two types of Carbon atoms  wich is a cyclohexadiene (it supposes to have only two signals in NMR). The generated spectra on the second picture proves that. And after hydration it becomes ordinary cyclohexane.

girl imma just put my comment here because i need a couple point okurrttt

consider the reaction below.

 no rx

at 500 k, the reaction is at equilibrium with the following concentrations.

[pci5]= 0.0095 m

[pci3] = 0.020

[ci2] = 0.020 m

what is the equilibrium constant for the given reaction?

0.042

0.42

2.4

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