Write the net ionic equation for the following molecular equation.
3mnbr2(aq) + 2na3po4(aq) → mn3 (po4)2(s) + 6nabr(aq)

Net ionic equation:

3Mn⁺²(aq)  + 2PO₄³⁻(aq)  →  Mn₃(PO₄)₂ (s)

Explanation:

Chemical equation:

MnBr₂(aq) +  Na₃PO₄(aq)  →  Mn₃(PO₄)₂ (s) + NaBr(aq)

Balanced chemical equation:

3MnBr₂(aq) +  2Na₃PO₄(aq)  →  Mn₃(PO₄)₂ (s) + 6NaBr(aq)

Ionic equation:

3Mn⁺²(aq)  + 3Br₂²⁻(aq) +  2Na₃³⁺(aq)  + 2PO₄³⁻(aq)  →  Mn₃(PO₄)₂ (s) + 6Na⁺(aq)  + 6Br⁻(aq)

Net ionic equation:

3Mn⁺²(aq)  + 2PO₄³⁻(aq)  →  Mn₃(PO₄)₂ (s)

The Br⁻ and Na⁺ are spectator ions that's why these are not written in net ionic equation. The  Mn₃(PO₄)₂  can not be splitted into ions because it is present in solid form.

Spectator ions:

These ions are same in both side of chemical reaction. These ions are cancel out. Their presence can not effect the equilibrium of reaction that's why these ions are omitted in net ionic equation.  

the answer is 0.8m.

by: nicholas