During an experiment, a student adds 0.339 g of calcium metal to 100.0 ml of 2.05 m hcl. the student observes a temperature increase of 11.0 °c for the solution. assuming the solution's final volume is 100.0 ml , the density is 1.00 g/ml , and the specific heat is 4.184 j/(g⋅°c) , calculate the heat of the reaction, δhrxn . ca(s) 2h (aq)⟶ca2 (aq) h2(g)

The heat of the reaction is 17.94 J.

Explanation:

mass of Ca (m) = 0.339 g

increase in temperature (∆T)= 11°C

specific heat (s)= 4.184 J/(g. °C)

Now, to calculate the total heat we will have to multiply the mass with specific heat and increase in temperature.

∆H = m × s × ∆T

      = 0.339 × 4.184 × 11

      = 17.94 J

c-14 is carbon-14, or radiocarbon.   it is a radioactive isotope of carbon with an atomic nucleus containing 6 protons and 8 neutrons.

it is a solid

explanation: