Propane, c3h8, burns to produce carbon dioxide and water by the equation below. what is the coefficient in front of the carbon dioxide in the balanced equation? c3h8 + o2 \rightarrow→→ co2 + h2o

3

Explanation:

The unbalanced combustion reaction of the oxidation of propane is shown below as:-

On the left hand side,

There are 3 carbon atoms and 8 hydrogen atoms and 2 oxygen atoms

On the right hand side,

There are 1 carbon atom and 2 hydrogen atoms and 3 oxygen atoms

Thus,

Right side, must be multiplied by 3 and by 4 so to balance carbon and hydrogen.

Left side, is multiplied by 5 so to balance the whole reaction.

Thus, the balanced reaction is:-

Coefficient in front of the carbon dioxide in the balanced equation - 3

away from the curb

explanation:

the wheels would then hit the curb if it started to rolling, decreasing the chance of an accident.

1. a)c-14 has two more protons

2. d)they have different numbers of protons, neutrons, and valence electrons; they are all gases at room temperature.

3. c) iron and nickel.