Chemistry, 05.11.2019 05:31 queenhall934

The ph of an acid solution used to etch aluminum varies somewhat from batch to batch. in a random sample of 65 batches, the mean ph was 2.5. let µ represent the mean ph for all batches of this solution. suppose that the p-value for testing h0 : μ = 2.5 versus h1 : μ > 2.5 turns out to be 0.014.
which of the following is the best interpretation of the p-value?

a) there is a 1.4% probability that the mean of all the batches is equal to 2.5.
b) there is a 1.4% probability that the mean of all the batches is greater than 2.5.
c) if the mean of all the batches is actually equal to 2.5, then the observed sample mean is in the most extreme 1.4% of its distribution
d) if the mean of all the batches is actually greater than 2.5, then the observed sample mean is in
the most extreme 1.4% of its distribution

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Answer from: Quest

the answer is c. nacl

Answer from: Quest

definition

entropy is a measure of the randomness or the extent of disorder of a chemical process.

enthalpy is a measure of the heat change of a reaction occurring at a constant pressure.

measurement units:

entropy is measured in joule per kelvin (jk⁻¹) whereas enthalpy is measured in joule per mole (jmol⁻¹)

requirements:

entropy has no requirements or limits, and its change is measured by the division between the heat change of the chemical process and the temperature.

in contrast, enthalpy can only be related to the heat change of the reaction under standard conditions.

Answer from: Quest

The answer is d.potassium

Answer from: Quest

answer : (a) volume of the gas = 8.67 × $10^{-3}$ l

(b) second virial coefficient b = -1.21226 l/mole

solution : given, t = 300k

p = 20atm

z = 0.86

n = 8.2 mmoles = 8.2 × $10^{-3}$ moles

r = 0.082 l atm/k/mol

find, (a) volume of gas and (b) second virial coefficient b at 300k.

formula used : $z=\frac{pv}{nrt}$

and $z=1+\frac{b}{v}$

(a) $z=\frac{pv}{nrt}$

$v=\frac{znrt}{p}$

= $\frac{0.86\times 8.2\times[tex]10^{-3}$ \times 0.082\times 300}{20}[/tex]

= 8.67 × $10^{-3}$ l

(b) $z=1+\frac{b}{v}$

$b=(z-1)v$

= (0.00867-1) × 8.659

= - 8.5839 l/mole

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