Enter your answer in the provided box. when 0.100 mol of caco3(s) and 0.100 mol of cao(s) are placed in an evacuated, sealed 10.0−l container and heated to 385 k, pco2 = 0.220 atm after equilibrium is established: caco3(s) ⇌ cao(s) + co2(g) an additional 0.240 atm of co2(g) is pumped in. what is the total mass (in g) of caco3 after equilibrium is reestablished?

Explanation:

Hi, step by step:

1) In equilibrium:

Assuming ideal gas:

In molarity:

2) Equilibrium constant:

For the given chemical reaction, the constant expression is:

Note: CaCO3 and CaO are not considered because they are in solid state

3) Concentrations in equilibrium:

Initial: 0.01 M of CaCO3 and 0.01 M of CaO

If 0.00697 M of dioxide where produced, also the same amount of CaO was produced. On the other side, 0.00697 M of CaCO3 where consumed. So:

Final: (0.01-0.00697) M of CaCO3, 0.00697 M of CO2 and (0.01+0.00697)M of CaO

4) Adding CO2

Aditional CO2: 0.24 atm:

The sistem will try to get back to equilibrium consuming those moles of CO2.

Following the inverse reaction, if 0.0076 M of CO2 are consumed, 0.0076 M of CaCO3 are produced:

The mass:

answer: cellular respiration takes in food and uses it to create atp, a chemical which the cell uses for energy. usually, this process uses oxygen, and is called aerobic respiration. it has four stages known as glycolysis, link reaction, the krebs cycle, and the electron transport chain.