Cu + h₂o → cuo + h₂ this equation shows that cu is . this equation shows that h₂ is .

Cu is oxidized and H₂ is reduced.

Explanation:

Given chemical equation,

On observing the equation, if we write the oxidation states of all elements in the compounds, we will get

In this equation,

Oxidation number of 'Cu' is increased from 0 to 2. Hence it is oxidized. While the oxidation number of 'H₂' is decreased from +1 to 0. Hence it is reduced.

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally