Given 2.14g of b2h6
(a) the number of moles of b2h6 in this sample
(b) the number of b2h6 moles in this sample
(c) the number of hydrogen atoms in this sample

i need with these three questions—- show work : (

(A) is 0.0773 mol B2H6

(C) is 2.79 x 10^23 H atoms

Explanation:

Questions (A) and (B) are the same.

2.14 g B2H6 x (1 mol B2H6/27.668g B2H6) = 0.0773 mol B2H6 (A)

27.668 is the molar mass of B2H6 calculated from the period table:

(2 x 10.81) + (6 x 1.008) = 27.668

1.008 is the mass of H and 10.81 is the mass of B

(C)

0.0773 mol B2H6 x (6 mol H/ 1 mol B2H6) x (6.022 x 10^23 H atoms/1 mol H)

= 2.79 x 10^23 hydrogen atoms

Further Explanation:

answer; the numbers of valence electrons in the acetic acid molecule (ch3co2h) is 24;