(f) which of the following alkenes is the major product when 2-bromo-2-methylpentane is treated with sodium ethoxide in ethanol?
a) (e)-4-methylpent-2-ene
b) (z)-4-methylpent-2-ene
c) 2-methylpent-1-ene
d) 2-methylpent-2-ene
e) 4-methylpent-1-ene

The major product when 2-bromo-2-methylpentane is treated with sodium ethoxide in ethanol is: 2-methylpent-2-ene

Explanation:

The elimination reaction generates the most substituted alkene (Zaitsev's rule)

Hence, the major product when 2-bromo-2-methylpentane is treated with sodium ethoxide in ethanol is 2-methylpent-2-ene.

In the attached picture, you can see that the 2-methylpent-1-ene is less substituted

c-14 is carbon-14, or radiocarbon.   it is a radioactive isotope of carbon with an atomic nucleus containing 6 protons and 8 neutrons.

a. energy is absorbed in the reaction.

if in a given reaction the energy of products is greater than the energy of reactants it means that reaction is endothermic and during the reaction, the energy is absorbed by reactants. in an endothermic reaction, the products have more stored chemical energy than the reactants. and in this reaction the reactants are more stable than products before the compounds with less energy are always more stable.