What is the change in heat energy when 64.82 g of aluminum metal at 100.0oc is cooled to 82.0 °c? the specific heat of aluminum is 0.897 j /g °c.

Given:

64.82 g of aluminum metal

100.0oC is cooled to 82.0 °C

specific heat of aluminum is 0.897 J /g °C.

Required:

Change in heat energy

Solution:

This can be solved through the equation H = mCpT where H is the heat, m is the mass, Cp is the specific heat and T is the change in temperature.

The specific heat of the water is 4.18 J/g-K

Plugging in the values into the equation

H = mCpT

H = (64.82) (0.897 J /g °C) (82 – 100)

H = -1,046.6 J

i just learnt this recently but i need to look through my notes again