Find the vapor pressure of a water solution in which the
molefraction of hgcl2 (a nonvolatile solute) is 0.163 at 25 °c.

The vapor pressure in solution is 0,0051 atm

Explanation:

This is the formula for vapor pressure lowering, the colligative property.

P vapor = Pressure sv pure . Xsv

Where Xsv is data.

Xsv means Molar fraction (moles solvent/total n° moles)

Vapor pressure of water, pure is 17.5 mmHg

P vapor = 0,0313 atm . 0163

P vapor in solution = 0,0051 atm

Molar fraction does not have units

A solution will have less vapor pressure than that observed in the pure solvent.

your answer is c) plasma

~*"auba14"*~