The reaction, 2 no(g) + cl2(g) → 2 nocl(g) was studied at -10oc. the following results were obtained. [no] (m) [cl2] (m) initial rate (m min-1) 0.10 0.10 0.18 0.10 0.20 0.36 0.20 0.20 1.45 a) what is the rate law? b) what is the value of the rate constant? (include correct units)

Answer :

(a) The rate law becomes:

(b) The value of the rate constant 'k' for this reaction is

Explanation :

Rate law : It is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

For the given chemical equation:

Rate law expression for the reaction:

where,

a = order with respect to

b = order with respect to

Expression for rate law for first observation:

....(1)

Expression for rate law for second observation:

....(2)

Expression for rate law for third observation:

....(3)

Dividing 1 from 2, we get:

Dividing 2 from 3, we get:

(a) Thus, the rate law becomes:

(b) Now, calculating the value of 'k' by using any expression.

Putting values in equation 1, we get:

Hence, the value of the rate constant 'k' for this reaction is

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explanation:

because it is

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally