Based on the following balanced equation- how many grams of zinc oxide could be generated from 1.75 miles of zinc sulfide assuming there was excess oxygen?
c = 12.01, o = 16.00, zn = 65.38 (g/mol)

mass of ZnO = 142.42 g  

Explanation:

Balanced chemical equation  

       2ZnS + 3O₂ → 2ZnO  + 2SO₂

Given data from eq.

     moles of zinc sulfide = 2 mol  

     moles of zinc oxide = 2 mol  

     mass of zinc oxide = ?

     Given moles of  

zinc sulfide = 1.75 mol

Solution  

1st we will find out the mole ratio of zinc sulfide and zinc oxide from balanced chemical equation  

          ZnS : ZnO

               2 : 2

            2/2 : 2/2

                 1 : 1  

given number of moles of zinc sulfide = 1.75 mol

So we can find out moles (x) of ZnO  needed for 1.75 mol of zinc sulfide  

from the balanced chemical equation the mole ratios are:  

               1 : 1  

          1.75 : x  

Cross multiply these ratios  

        1 × 1.75 = 1x  

             1.75 = 1 x  

             x = 1.75 mol  

Now we will find out the mass of ZnO

    mass = moles × molar mass  

    mass of ZnO = 1.75 mol × 81.38 g/mol  

    mass of ZnO = 142.42 g  

i can ! i just need to know what the paragraph is! : p

assuming that your periodic table has eighteen columns, you should highlight   the four elements in the third column from the left of the table.

neutral atoms of elements after calcium contain d electrons. the energy of d orbitals of a particular main shell lies between the energy of the s and p orbitals of the next main shell. for example, electrons in the have energy higher than those in the orbital while lower than those of the orbital.

by the aufbau principle, electrons fill orbitals one at a time, starting from those of the lowest energy. the orbital is therefore filled right after orbitals and before orbitals.  

potassium has electron configuration and calcium . the s orbital of a main shell holds a maximum of two electrons. the next element would thus have the electron configuration and satisfy the requirements.

a neutral atom of the element contains three electrons on top of the most recent noble gas element. it should thus be placed in the third column of the periodic table. both scandium and yttrium would satisfy the conditions. an aufbau diagram indicates that the 4f orbital is filled before the 5d. however, it appears that exceptions exists for both lanthanum and actinium. neutral atoms of the two d-block elements also demonstrate the and should be highlighted as well.