Are benzene, sodium bromide, glucose, and pentane more soluble in octane or water, explain why?

Here's what I get  

Explanation:

Benzene and pentane: more soluble in octane. Both substances are nonpolar, so their molecules can easily intermingle with each other.

Sodium bromide: more soluble in water. The polar water molecules hydrate the ions to form Na⁺(aq) and Cl⁻(aq).

Glucose: more soluble in water. A glucose molecule has six OH groups and these can form hydrogen bonds with the water molecules.

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g

2b2t

explanation:

2b2t