Explain how you would calculate the q for warming 100.0 grams of liquid water from 0°c to 100 °c.

The answer to your question is:

Explanation:

Data

mass = 100 g

T1 = 0°C

T2 = 100 °C

C = 1 cal/g°C

Process

1.- Do a list of all the data given

2.- Look in books or tables the specific heat of water.

3.- Check that the variables have the same units

4.- Write the formula

5.- Substitute the data

6.- Do the operations

           Q = mC(T2 -T1)

           Q = 100(1)(100 - 0)

           Q = 100(100)

           Q = 10000 cal

the answer is 0.42 is that is an option. this question provides no info