Which of the following solutions is a buffer? check all that apply. check all that apply. a solution made by mixing 100 ml of 0.100 m hclo and 50 ml of 0.100 m naoh a solution made by mixing 100 ml of 0.100 m hclo and 50 ml of 0.100 m hcl a solution made by mixing 100 ml of 0.100 m kclo and 50 ml of 0.100 m kcl a solution made by mixing 100 ml of 0.100 m hclo and 500 ml of 0.100 m naoh

A solution made by mixing 100 mL of 0.100 M HClO and 50 mL of 0.100 M NaOH IS A BUFFER

A solution made by mixing 100 mL of 0.100 M HClO and 50 mL of 0.100 M HCl IS NOT A BUFFER

A solution made by mixing 100 mL of 0.100 M KClO and 50 mL of 0.100 M KCl IS NOT A BUFFER

A solution made by mixing 100 mL of 0.100 M HClO and 500 mL of 0.100 M NaOH IS NOT A BUFFER

Explanation:

A buffer is a mixture of a solution a weak acid and its conjugate base, or vice versa.

Thus, a solution by mixing 100 mL of 0.100 M HClO and 50 mL of 0.100 M NaOH IS a buffer because: HClO + NaOH → NaClO. Here, weak acid is HClO and its conjugate base is NaClO

A solution made by mixing 100 mL of 0.100 M HClO and 50 mL of 0.100 M HCl IS NOT a buffer because HClO + HCl produce Cl₂ that is a gas. You don't produce the cojugate base

A solution made by mixing 100 mL of 0.100 M KClO and 50 mL of 0.100 M KCl IS NOT a buffer because these salts will not produce HClO.

a solution made by mixing 100 mL of 0.100 M HClO and 500 mL of 0.100 M NaOH IS NOT a buffer because here you have NaOH in excess. That means that all HClO will produce NaClO. In the solution you will have just the conjugate base and not its weak acid.

I hope it helps!

indium, and thallium have three electrons i think