Rank the following 0.10 m solutions in order of increasing ph (lowest ph to highest ph): hcl hf nacl hoclrank the following 0.10 m solutions in order of increasing ph: hc2h3o2 nacl nh3 hcl koh

1) The ranked solutions from the lowest pH to the highest pH are:

HCl < HF < HClO < NaCl

2) The ranked solutions from the lowest pH to the highest pH are:

HCl < CH₃COOH < NaCl < NH₃ < KOH

Explanation:

1) HCl is a strong acid because the concentration of the undissociated species HCl is too low to be measured. A 0.1 M solution of HCl is pH=1

pH=-log[H₃O⁺]=-log[0.1]=1

HF and HClO are weak acids because they partially dissociates when they are dissolved in a solvent.

HF pKa =3.17 ⇒ Ka==6.761×10⁻⁴

pH= = -log[√(0.1×6.761×10⁻⁴)]=2.1

HClO pKa=7.49 ⇒ Ka==3.236×10⁻⁸

pH= = -log[√(0.1×3.236×10⁻⁸)]=4.2

NaCl is a neutral salt. The pH of the solution is 7.

HCl < HF < HClO < NaCl

2) HCl is a strong acid because the concentration of the undissociated species HCl is too low to be measured. A 0.1 M solution of HCl is pH=1

KOH is a strong base because the concentration of the undissociated species KOH is too low to be measured. A 0.1 M solution of KOH is pOH=1 ⇒ pH= 14 - pOH = 13

CH₃COOH (acetic acid) is a weak acid whose pKa=4.76

Ka==1.738×10⁻⁵

pH= = -log[√(0.1×1.738×10⁻⁵)]=2.88

NH₃ is a weak base whose pKb=5 ⇒ ⇔Kb=1×10⁻⁵

NH₃ + H₂O ⇔ NH₄⁺ + OH⁻

[OH⁻]== 1×10⁻³

pOH=-log[1×10⁻³]=3

pH=14-pOH= 11

Hence, the rank should be:

HCl < CH₃COOH < NaCl < NH₃ < KOH

the positions which points up in upward carbon and down in downward carbon are axial

and vice versa holds true for equatorial positions

so the correct answer with labelled diagram will be