How many grams of fosforic acid (h3po4) are required to prepare 500 ml of a 0.2 m solution?

Mass = 9.8 g

Explanation:

Given data:

Molarity of solution = 0.2 M

Volume of solution = 500 mL

Number of grams of phosphoric acid = ?

Solution:

First of all we will convert the volume milliliter to litter.

500 mL × 1 L/1000 mL

0.5 L

Molarity = moles of solute / volume in litter

0.2 M =  number of moles / volume in litter

Number of moles = 0.2 mol/L × 0.5 L

Number of moles = 0.1 mol

Number of grams:

Number of moles = mass/molar mass

Mass = number of moles × molar mass

Mass = 0.1 mol × 98 g/mol

Mass = 9.8 g

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explanation:

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explanation:

covalent bonds

consist of pairs of electrons shared by two atoms, and bind the atoms to fixed orientation and requre high energies to break them

ionic bonds

when two atoms differ considerably in their electronegativity, then one of the atoms will lose its electron to the other atom. this results in a positively charged ion(cation) and a negatively charged ion (anion)