4. copper metal reacts with nitric acid(hno3) to produce aqueous copper (ii)nitrate, nitrogen dioxide gas and liquid water. a. write the balanced equation for the reaction b. if there are 0.500 moles of copper metal present how many moles of nitric acid are required for the reaction? how many moles of nitrogen dioxide gas are formed?

a.

b.

Explanation:

a. For the balanced equation we have to obtain the same amount of atoms in both sides:

b. If we want to calculate the moles of nitric acid we have to use the molar ratio in the balence reaction:

For the moles of nitrogen dioxide we have to follow the same logic:

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :

no, the red giant is the hottest with 2.00.000.000 degrees celsius. while the white dwarf only 25,000 degrees celsius.