Chemistry, 17.10.2019 05:00 trinityanne1738
At equilibrium, the concentrations in this system were found to be [n2]=[o2]=0.200 m and [no]=0.600 m. n2(g)+o2(g)↽−−⇀2no(g) if more no is added, bringing its concentration to 0.900 m, what will the final concentration of no be after equilibrium is re‑established?
Answers: 1
![K_{eq}=\frac{[NO]^2_{eq}}{[N_2]_{eq}[O_2]_{eq}} \\K_{eq}=\frac{0.6^2}{0.2*0.2}\\ K_{eq}=9](/tpl/images/0327/3782/fd314.png)
![9=\frac{[NO]^2_{eq}}{[N_2]_{eq}[O_2]_{eq}}\\9=\frac{[0.9+2x]^2}{[0.2-x][0.2-x]}](/tpl/images/0327/3782/c867b.png)
![\frac{1}{9} =\frac{[N_2]_{eq}[O_2]_{eq}}{[NO]^2_{eq}}\\\frac{1}{9} =\frac{[0.2+x][0.2+x]}{[0.9-2x]^2}](/tpl/images/0327/3782/3755f.png)
![[NO]_{eq}=0.9-0.06=0.84M](/tpl/images/0327/3782/19d1e.png)
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At equilibrium, the concentrations in this system were found to be [n2]=[o2]=0.200 m and [no]=0.600...
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