If a 100 kg mol mixture of n-hexane and n-octane containing 50 mole% n-hexane is to be separated by flash distillation @ 1 atm to obtain 40 kg mol in distillated (ie. v=40 kg mol) a) whatare the compositions of the liquid and vapor phases when v = 40 kg mol? b) what is the flash drum temperature?

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confused

confused             hewdejdnjnjsnd

i belive it is water

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally