Awaste gas contains 0.1 mol% toluene in air and occupies a volume of 2,120 m3 at 298 k and 116 kpa. in an effort to reduce the toluene content of this gas, it is exposed to 113 kg of activated carbon, initially free of toluene. the system is allowed to reach equilibrium at constant temperature and pressure. assuming that the air does not adsorb on the carbon, calculate (a) the equilibrium mole fraction of toluene in the gaseous phase and (b)the amount of toluene adsorbed by the carbon. the adsorption equilibrium for this system is given by the freundlich isotherm: w = 0.208(p*)^0.11. in this equation w is the carbon equilibrium adsorptivity, in kg of toluene/kg of carbon, and p* is the equilibrium toluene partial pressure, in pa. (mw of toluene = 92)