Oxygen-16 (15.994915 amu) is synthesized in the sun by fusion of carbon-12 (12. amu) and helium-4
(4.00260 amu). how much energy is released in this nuclear reaction?
3.82 x 10-18 kj
x 10-15
1.20 x 101

1.142 × 10⁻¹⁵ kJ

Explanation:

Total mass of C-12 and He-4 = 12.00000 + 4.00260 = 16.00260 amu

mass of O-16 = 15.99495 amu

Difference in mass = 16.00260 - 15.99495 = 0.00765 amu

The difference in mass 0.00765 is converted into energy.

It is known that,

1 amu = 931.46 MeV

then,

0.00765 amu × 931.46 MeV /amu = 7.1257 Mev

In joule:

1.142 × 10⁻¹⁵ kJ

Because 1 MeV = 1.6 × 10⁻¹⁶ Kj

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when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml