Compound a, c12h22o, undergoes reaction with dilute h2so4 at 50°c to yield a mixture of two alkenes, b and c, c12h20. the major alkene product, b, gives only cyclohexanone after ozone treatment followed by reduction with zinc in acetic acid. draw the strtucture of the major alkene product, compound b.

The answer to your question is:

Explanation:

Cyclohexanone is a cyclic molecule composed by 6 carbons and 1 ketone group.

Molecular formula C₆H₁₀O

the correct answer is b. a strong acid completely dissociates to its ions when dissolved in water. completely dissociates to and ions. a is incorrect because does not fully ionize to and ions and some remain as the compound . c and d are incorrect because, and do not fall into the category of bronsted lowry acids. a bronsted lowry acid is a proton donor and since both molecules do not have a proton to donate they are not bronsted lowry acids. likewise,   if we use the lewis acid definition, they cannot be acids. a lewis acid is an electron pair acceptor. both and have a complete octet so can not accept any electrons which disqualifies them as acids.