The decomposition of n2o to n2 and o2 is a first-order reaction. at 730°c, the rate constant of the reaction is 1.94 × 10-4 min-1. if the initial pressure of n2o is 4.70 atm at 730°c, calculate the total gas pressure after one half-life. assume that the volume remains constant. slatter

Total pressure 5.875 atm

Explanation:

The equation for above decomposition is

rate constant

Half life

Initial pressure

Pressure after 3572 min = P

According to first order kinematics

solving for P we get

P = 2.35 atm

initial           4.70                         0             0

change        -2x                          +2x           +x

final             4.70 -2x                     2x           x

pressure of after first half life  = 2.35 = 4.70 - 2x

                                                          x = 1.175

pressure of after first half life  =  2x = 2(1.175) = 2.35 ATM

Total pressure  = 2.35 + 2.35 + 1.175

                          = 5.875 atm

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