A5.00-wt% aqueous sulfuric acid solution (p=1.03 g/ml) flows through a 45-m long pipe with a 6.0 cm diameter at a rate of 82 l/min. a) what is the molarity of sulfuric acid in the solution? b) how long in seconds) would it take to fill a 55-gallon drum, and how much sulfuric acid (lbm) would the drum contain? c) the mean velocity of a fluid in a pipe equals the volumetric flow rate divided by the cross-sectional area normal to the direction of flow. use this information to estimate how long (in seconds) it takes the solution to flow from the pipe inlet to the outlet.

Answerthis solution will not form a precipitateexplanationsolubility equilbrium:         pbf₂(s)  ⇄ pb²⁺(aq) + 2 f⁻(aq)the solubility product expression is    (we exclude solids from the equilibrium expression).now suppose we have the trial ion product q, which we can define as    then, we can interpret  q as the product of the concentration of the ions that we have and ksp as the product of the ion concentrations that are needed to form a saturated solution.if q > ksp, then that implies that there will be a surplus of ions that exceed the amount that is required to form a saturated solution. a precipitate will then form (the precipitate continually  forms until the surplus ions are removed and q is decreased to ksp's value).if q = ksp, the saturated solution that forms is barely saturated and the precipitate will be minimal.if q < ksp, then the ion concentration will not be enough to form a saturated solution (so no precipitate).using our information, we calculate the trial ion product:     since q = 2.7  × 10⁻⁸ < ksp =  4  ×  10⁻⁸, a precipitate will not form.

The ratio is 3: 2. i.e. c.