A76.0 ml aliquot of a 1.40 m solution is diluted to a total volume of 208 ml. a 104 ml portion of that solution is diluted by adding 153 ml of water. what is the final concentration?

The answer to your question is:        Molarity = 0.30

Explanation:

Data

V1 = 76 ml

C1 = 1.4 M

V2 = 208 ml

V3 = 104 ml

V water = 153 ml

Process

                          C1V1 = C2V2

                         C2 = C1V1/ V2

                         C2 = (1.4)(76) / 208

                         C2 = 0.51 M

Molarity = moles / volume

moles = Molarity x volume

moles = 0.51 x 0.208

moles = 0.11                      Final volume = 0.208 + 0.153

                         Molarity = 0.11 / 0.361

                         Molarity = 0.30

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it forms an anion that has a larger radius. anions have a negative charge and are larger than the original atom.