What is the oxidation state of each element in mn(cro4)2?

The The oxidation state of each element in Mn(Cro4)2 is

Oxidation state of  Mn is  +4

Oxidation state of  is -2

Oxidation state of Cr is +6

Explanation :

The oxidation number denotes the number of electrons the atom loses in a chemical compound.

Also, oxidation number is equal to the charge of the ion. In the above compound oxidation state of Cro4 is -2 and there are two ions together. Thus, there oxidation state would be -4.

Mn have the oxidation state of +4. And oxidation charge of oxygen is always -2. In equation Cro4 there are 4 oxygen each having oxidation charge of -2. Making it -8 in total. Cro4 has its oxidation charge of -2. Thus adding up the charges it turns out to be +6 for chromium.    

93.2 ml + 3920 ml = 4013 ml total  

(93.2 ml) * (2.03 m) / (4013 ml) = 0.0471 m

the volume in in l of the diluted solution would be 0.0471 m.

ill try to . no promises tho.

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