Calculate the heat released when 25.0 grams of water freezes at 0 degree celsius.

= 8350 joules

Solution and explanation:

Therefore; For 25.0 g of water.

Heat released = Mass of water × heat of fusion

                        = 25 g × 334 J/g

                        = 8350 Joules

Hence, the amount of heat released when 25.0 g of water freezes at 0°C is 8350 J.

*tilts head* sounds more like a statement

answer:

the reaction is type of combination reaction.

explanation:

on the product side, there are 2 molecules of bonded to fe   which means one atom of fe are combined two molecules of . so, balanced chemical equation becomes :

this reaction follows the reaction type of combination reaction. a combination reaction is defined as chemical reaction in which reactants combines together to form a single product.