Use standard enthalpies of formation to determine δhorxn for: 2c2h2(g) + 5o2(g) → 4co2(g) + 2h2o(l)

The answer to your question is:              ΔHr = - 2598.8 kJ/mol

Explanation:

                       2C₂H₂(g) + 5O₂(g) → 4CO₂(g) + 2H₂O(l)

Enthalpies

C₂H₂(g) = 226.9 kJ/mol

O₂(g)   = 0 kJ/mol

CO₂(g) = -393.5 kJ/mol

H₂O(l)  = -285.5 kJ/mol

Formula

                ΔH r = ∑npHp - ∑nrHp

Process

             ΔHr = 4(-393.5) + 2(-285.5) - 2(226.9)

            ΔHr = -1574 - 571 - 453.8

           ΔHr = - 2598.8 kJ/mol

answer: a chemical reaction

explanation:

im not wrong

true

hope that