Chemistry, 10.10.2019 05:30 yhbgvfcd6677

An aqueous solution of sodium hydroxide contains 15% naoh by mass. it is desired to produce an 5% naoh solution by diluting a stream of the 15% solution with a stream of pure water. calculate the following: a) the ratios (g h, o/g feed solution) and (g product / g feed solution). b) determine the feed rates of 15% solution and diluting water needed to produce 2500 ib./min of the 5% solution.

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Answer from: dsporski

Explanation:

We will assume that the flow rate of feed (F) = 100 g/min

(a) The overall mass balance will be as follows.

Total mass IN = Total mass OUT

as, Feed + Pure water = Product

100 + W = P

or, P - W = 100 .......... (1)

Whereas NaOH mass balance will be as follows.

Total NaOH mass IN = Total NaOH OUT

NaOH in feed + NaOH in water = NaOH in product

$\frac{20}{100} \times F + 0 = \frac{8}{100} \times 100$

P = $\frac{20}{100} \times 100 \times \frac{100}{8}$

= 250 g/min

Now, we will put the value of P in equation (1) as follows.

P - W = 100

250 - W = 100

W = 250 - 100

= 150 g/min

Therefore, $\frac{\text{grams of pure water}}{\text{grams feed solution}}$ = $\frac{W}{F}$

= $\frac{150}{100}$

= 1.5

$\frac{\text{grams of product}}{\text{grams feed solution}}$ = $\frac{P}{F}$

= $\frac{250}{100}$

= 2.5

(b) As it is given that 8% solution (P) = 2400 lb/min.

As it is calculated that the ratio of P and F ( $\frac{P}{F}$ ) = 2.5

So, F = $\frac{P}{2.5}$

= $\frac{2400}{2.5}$

= 960 lb/min

Also, $\frac{W}{F}$ = 1.5

W = $1.5 \times F$

= $1.5 \times 960$

= 1440 lb/min

Therefore, we can conclude that the feed rate of 20% solution = F = 960 lb/min.

When diluted with water then W = 1440 lb/min.

Answer from: Quest

answer: e. sour taste

explanation: acids are those substances which dissociates in water to give $h^+$ ions. as they dissociate to give ions, they act as electrolytes and thus are electrically conductive. acids are sour in taste. example: hcl

$hcl\rightarrow h^++cl^-$

bases are those substances which dissociates in water to give $oh^-$ ions or accepts $h^+$ ions. as they dissociate to give ions, they act as electrolytes and thus are electrically conductive. bases are bitter in taste. bases are slippery in nature.

$naoh\rightarrow na^++oh^-$

$nh_3+h^+\rightarrow nh_4^+$

Answer from: Quest

what is the question here. i think you messed up.

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An aqueous solution of sodium hydroxide contains 15% naoh by mass. it is desired to produce an 5% na...

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