46.3 wt%a, 23.15 wt%b and 30.55 wt%c. assume the densities in g/cu. cm of a, b andc are 2.68, 5.86 and 10.39, respectively. determine the approximate density in g/cu. cm if the alloy is composed of

Answer : The approximate density is

Explanation :

The formula used to calculate the density of the mixture is,

where,

= density of mixture = ?

= mass of fraction of component A = 46.3 % = 0.463

= mass of fraction of component B = 23.15 % = 0.2315

= mass of fraction of component C = 30.55 % = 0.3055

= density of component A =

= density of component B =

= density of component C =

Now put all the given values in the above formula, we get:

Therefore, the approximate density is

- lead + phosphoric acid = hydrogen + lead(ii) phosphate