For the following reaction, kc = 15 at 700 k. 2 no(g) + cl2(g) ⇄ 2 nocl(g) if we have [no] = 0.15 m, [cl2] = 0.15 m, [nocl] = 0.40 m at 700 k, what will happen? group of answer choices the equilibrium will not shift. the equilibrium will shift to the left, but will use up only part of the nocl. the equilibrium will shift to the right, but will use up only part of the no and cl2. the equilibrium will shift to the right until all the reactants are used up. the equilibrium will shift to the left until all the nocl is used up.

Answer : The correct option is, The equilibrium will shift to the left until all the NOCl is used up.

Explanation :

Reaction quotient (Q) : It is defined as the measurement of the relative amounts of products and reactants present during a reaction at a particular time.

The given balanced chemical reaction is,

The expression for reaction quotient will be :

In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted.

Now put all the given values in this expression, we get

The given equilibrium constant value is,

Equilibrium constant : It is defined as the equilibrium constant. It is defined as the ratio of concentration of products to the concentration of reactants.

There are 3 conditions:

When that means product > reactant. So, the reaction is reactant favored.

When that means reactant > product. So, the reaction is product favored.

When that means product = reactant. So, the reaction is in equilibrium.

From the above we conclude that, the that means product > reactant. So, the reaction is reactant favored that means reaction must shift to the reactants to be in equilibrium or shift to the left side.

Hence, the correct option is, The equilibrium will shift to the left until all the NOCl is used up.

atomic number of carbon is 6

electronic configuration of carbon is 1s²2s²2p²

orbital diagram of c is as shown here in the image.