For the reaction
2
agno

3
+
na

2
cro

4
⟶
ag

2
cro

4
+2
nano

3
2agno3+na2cro4⟶ag2cro4+2nano3
how many grams of sodium chromate, na2cro4, are needed to react completely with
12.1
12.1
g of silver nitrate, agno3?

Mass of Na₂CrO₄ =  5.75 g

Explanation:

First of all we will write the balance chemical equation.

2AgNO₃ + Na₂CrO₄     →    Ag₂CrO₄  +  2NaNO₃

Now we will calculate the moles of AgNO₃.

Number of moles = mass / molar mass

Molar mass of AgNO₃ = 107.87 + 14 + 3× 16 =  169.87 g/mol

Number of moles = mass / molar mass

Number of moles = 12.1 g / 169.87 g/mol = 0.071 mol

Now we will compare the moles of AgNO₃ and  Na₂CrO₄ from balance chemical equation.

                        AgNO₃    :     Na₂CrO₄

                          2            :           1

                          0.071     :           1/2× 0.071 = 0.0355

Now we will calculate the mass of Na₂CrO₄.

Molar mass of Na₂CrO₄ = 23×2 + 52 + 16×4 = 162 g/mol

Mass of Na₂CrO₄ = number of moles  ×  molar mass

Mass of Na₂CrO₄ =  0.0355 mol ×  162 g/mol

Mass of Na₂CrO₄ =  5.75 g

frequency, z, and the collision density, z, in carbon dioxide (co2), r 180 pm at 30 °c and 120 kpa

water and alcohols have similar properties because water molecules contain hydroxyl groups that can form hydrogen bonds with other water molecules and with alcohol molecules, and likewise alcohol molecules can form hydrogen bonds with other alcohol molecules as well as with water.