H2so4 is an unusual diprotic acid in that the first dissociation is considered strong, but the second dissociation is weak. therefore, h2so4 only has ka2 = 1.2x10−2. consider an aqueous solution containing 0.010 m h2so4. calculate the concentration of so42− ions in this solution. calculate the concentration of hso4− ions in this solution. calculate the concentration of h3o+ ions the solution. enter each of your answers to two significant figures. do not use scientific notation.

Explanation:

As it is given that the initial concentration of sulfuric acid is 0.010 M.

Hence, the ICE table for first dissociation of sulfuric acid is as follows.

Initial:         0.010                       0        0

Change:     -0.010                +0.010    +0.010

Equilibrium:    0                    0.010        0.010

When second dissociation of sulfuric acid occurs which is partial then the ICE table will be as follows.

Initial:                 0.010                    0        0.010

Change:              -x                       +x          +x

Equilibrium:       0.010 - x              x            0.010 + x

Since, it is given that . Hence, formula  for is as follows.

                                x = 0.0045

Hence, by using the equilibrium concentrations from the table and value of x we get the following.

                    = 0.0045 M

                      = 0.010 - 0.0045

                      = 0.0055 M

                    = 0.010 + 0.0045

                    = 0.0145 M

what is the average time it took the car to travel 0.25 meters?

⇒ 2.23 seconds

what is the average time it took the car to travel 0.50 meters?

⇒ 3.13 seconds