Chemistry, 08.10.2019 01:00 hamadehassan
For the equilibrium pcl5(g) pcl3(g) + cl2(g), kc = 4.0 at 228°c. if pure pcl5 is placed in a 1.00-l container and allowed to come to equilibrium, and the equilibrium concentration of pcl5(g) is 0.26 m, what is the equilibrium concentration of pcl3?
Answers: 1
is, 1.0 M
= 0.26 M
= 4.0
![K_c=\frac{[PCl_3][Cl_2]}{[PCl_5]}](/tpl/images/0298/6790/73fe0.png)
are equal.
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For the equilibrium pcl5(g) pcl3(g) + cl2(g), kc = 4.0 at 228°c. if pure pcl5 is placed in a 1.00-l...
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