According to the balanced chemical equation

5 h2c2o4(aq) + 2 mno4-(aq) + 6 h+(aq) → 10 co2(g) + 2 mn2+(aq) + 8 h2o(l)

0.3500 grams of oxalic acid, h2c2o4 will react with ml of 0.100 m potassium permanganate, kmno4 solution.
a) 15.5 ml
b) 38.9 ml
c) 77.7 ml
d) 97.2 ml

A) 15.5 mL

Explanation:

Given, Mass of oxalic acid = 0.3500 g

Molar mass of oxalic acid = 90.03 g/mol

The formula for the calculation of moles is shown below:

Thus,

According to the given reaction:

5 moles of oxalic acid react with 2 moles of potassium permanganate

Thus,

1 mole of oxalic acid react with 2/5 moles of potassium permanganate

0.0038876 mole of oxalic acid react with moles of potassium permanganate

Moles of potassium permanganate = 0.001555 moles

Also, considering:

Molarity = 0.100 M

So,  

Volume = 0.01555 L

Also, 1 L = 1000 mL

So, volume = 15.5 mL

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