Apiece of aluminum foil 1.00cm square and 0.590mm thick is allowed to react with bromine to form aluminum bromide. part a how many moles of aluminum were used? (the density of aluminum is 2.699 g/cm^3 part b how many grams of aluminum bromide form, assuming that the aluminum reacts completely?

Part A: 5.899x10^-3 moles of Al

Part B: 1.573 g of AlBr3

Explanation:

Part A: We have to obtain the volume of the piece of aluminium; all sides of the square must be in cm. Then, use the density to obtain the mass.

0.059 is the volume of the Al udes for the reaction. Now, to oabtain the moles:

Part B: To obatin the mass of AlBr3, we need the balanced chemical equation:

                                               2Al + 3Br2 → 2AlBr3

We assume bromine (Br2) is in excess, therefore, we calculate the aluminum bromide formed from the Al:

of Al

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in chemistry, adhesion and cohesion are attractive forces that exist between molecules. they hold the molecules together from each other. they are different in that adhesive force exists between molecules of different substance while cohesive force happens between molecules of same substance.

adhesion between water and glass causes water molecules at the edge of water and glass interface to climb up the wall in a narrow glass tube. this is called capillary action. cohesion is what gives glass its shape and causes water to form a droplet.