Ablock of aluminum weighing 140 g is cooled from 98.4°c to 62.2°c with the release of 1080 joules of heat. from this data, calculate the specific heat of aluminum.

Specific heat of a substance is the value that describe how the added heat energy of substance has the impact on its temperature.

Unit is

C = Q/m. ∆T

C – Specific heat

Q- heat energy (J)

M – Mass (Kg)

∆T- change in temperature (K)

Explanation:

Given data:

M= 140 g = 0.14 Kg

Q – 1080 Joules.

∆T – 98.4 – 62.2 = 36.2

Substituting  the given data in Equation

Specific heat of Aluminium  =

Explanation:

Specific heat is defined as the amount of energy required to heat or cool 1 kg of a substance by 1°C.

It is given:

energy is 1080 joules,

mass is 140g; i.e. 0.14kg,

temperature change is 98.4 - 62.2 = 36.2°C

So the specific heat of aluminum = 1080 / 0.14 / 36.2

= 213.1 J/kg/°C

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