Acertain amount of gas at 25 c and at a pressure of 0.800 atm is contained in a glass vessel. suppose that the vessel can withstand a pressure of 2.00 atm. how high can you raise the temperature of the gas without bursting the vessel?

a. p1 / t1 = p2 / t2

b. so .8/298=2/t2

c. which equals 745 k

Answer :  745 K high you can raise the temperature of the gas without bursting the vessel.

Explanation :

Gay-Lussac's Law : It is defined as the pressure of the gas is directly proportional to the temperature of the gas at constant volume and number of moles.

or,

where,

= initial pressure of gas = 0.800 atm

= final pressure of gas = 2.00 atm

= initial temperature of gas =

= final temperature of gas = ?

Now put all the given values in the above equation, we get:

Therefore, the final temperature of the gas is 745 K

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