What volume in liters of 9.00×10^−2 m kh2aso4 contains 1.90 g kh2aso4?

The answer to your question is: Volume = 0.117 l

Explanation:

Data

V = ?

M = 9 x 10 ⁻²

mass = 1,9  g of KH₂AsO₄

MW KH₂AsO₄ = 39 + 2 + 75 + 64 = 180 g

Process

                       180 g of KH₂AsO₄  1 mol

                        1.9 g                         x

                      x = 0.0011 mol of KH₂AsO₄

Molarity = # of moles / volume

Volume = # of moles / molarity

Volume = 0.0011 mol of KH₂AsO₄ / 0.09

Volume = 0.117 l = 117 ml